×

#### Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
```
Spacecraft Voyager 2 (mass m and speed l' relative to the Sun) approaches the planet Jupiter (mass M and speed V relative to the Sun) as shown in Fig. The spacecraft rounds the planet and departs in the opposite direction. What is its speed, relative to the Sun, after this "slingshot" encounter? Assume that v = 12 km/s and V = 13 km/s (the orbital speed of Jupiter), and that this is an elastic collision. The mass of Jupiter is very much greater than the mass of the spacecraft, M >> m. (See "The Slingshot Effect: Explanation and Analogies," by Albert A. Bartlett and Charles W. Hord, The Physics Teacher; November 1985, p. 466.)
Spacecraft Voyager 2 (mass m and speed l' relative to the Sun) approaches the planet Jupiter (mass M and speed V relative to the Sun) as shown in Fig. The spacecraft rounds theplanet and departs in the opposite direction. What is its speed, relative to the Sun, after this "slingshot" encounter? Assume that v = 12 km/s and V = 13 km/s (the orbital speed of Jupiter), and that this is an elastic collision. The mass of Jupiter is very much greater than the mass of the spacecraft, M >> m. (See "The Slingshot Effect: Explanation and Analogies," by Albert A. Bartlett and Charles W. Hord, The Physics Teacher; November 1985, p. 466.)

```
5 years ago

Kevin Nash
332 Points
```
```
5 years ago
Kozerone
11 Points
```							Kevin Nash was right.$v_{2f}\approx2v_{1i}-v_{2i}$But how do we get there?Well, we have to use conservation of momentum and conservation of kinetic energy to get there, because this is an inelastic collision (KE is conserved). You will get two equations from the two conservation laws. The information $M \gg m$ is useful when you try to solve for $v_{2f}$ using these two equations, because it will allow you to make this expression: $(m/M)^2(v_{2f}+v_{2i})^2$ go to zero.  So you will not need to know what the value of $M$ is, to solve for $v_{2f}$.
```
2 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Mechanics

View all Questions »

### Course Features

• 101 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution

### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions