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Q 4 and 5 as in photo attached

Q 4 and 5 as in photo attached

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1 Answers

SHIVANSHU
39 Points
6 years ago
ans-(B)     after ball sticks to pan take it to eq. pos.
at this pos. KEmax=mgh+mg(mg/k)-(k/2)(mg/k)2
at maximum amplitude. P.E=KEmax=mgh+mg(mg/k)-(k/2)(mg/k)2=(k/2)A2 [A:amplitude]
solve for A.

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