Grade 12th passMechanics
Please provide proper solution to the question..image of the question is attached
Please provide proper solution to the question..image of the question is attached
1 Answer
Arun
Acc of the body =4-3v
Thus
dv/dt=4-3v
dv/(4-3v)=dt
Now integrating bothe sides by using substitution rule
ln(4-3v)/-3=t
ln(4-3v)=-3t
Now taking antilog on both sides
4-3v=e^(-3t)
Or 3v=4 - e^(-3t)
Now terminal velocity v=[4 - e^(-3t)]/3
Thus
dv/dt=4-3v
dv/(4-3v)=dt
Now integrating bothe sides by using substitution rule
ln(4-3v)/-3=t
ln(4-3v)=-3t
Now taking antilog on both sides
4-3v=e^(-3t)
Or 3v=4 - e^(-3t)
Now terminal velocity v=[4 - e^(-3t)]/3
hence terminal velocity = 4/3
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