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`        Please provide me with the answer for the attached question.urgent.please help`
one year ago

Arun
23382 Points
```							Reynolds number is given byR = ρvd/ηThe volume of the water flowing out per second isQ = v × πd2/4v = 4Q/d2πR = ρvd/ηR = 4ρQ/πdηρ = Density of water = 103 kg/m3Q = 3 L / min = 3 × 10-3 / 60 = 5 × 10-5 m3/sd = 2/√π × 10-2 m = 1.125 × 10-2 mη = Viscosity = 10-3 Pa.sSo, R = (4 × 103 × 5 × 10-5)/(3.14 × 1.125 × 10-2 × 10-3)R ≅ 5500
```
one year ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions