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please give the detailed solution of this .problem as soon as possible
please give the detailed solution of this .problem as soon as possible


2 years ago

Eshan
2095 Points
							Dear student,Since the springs are in parallel, the equivalent spring constant is$k_1+k_2$.For SHM starting from extreme position,Loss in potential energy= Gain in kinetic energy$\implies \dfrac{1}{2}(k_1+k_2)x^2-\dfrac{1}{2}(k_1+k_2)(\dfrac{x}{4})^2=\dfrac{1}{2}mv^2$$\implies v=\sqrt{\dfrac{15(k_1+k_2)}{16m}}x$

2 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions