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Solve ouestion number 2.

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Grade:11

1 Answers

Eshan
askIITians Faculty 2095 Points
5 years ago
Dear student,

At t=1second, the acceleration of man upwards=a_1=\dfrac{20-0}{2-0}m/s^2=10m/s^2

Hence the weight of man at this time=M(g+a_1)

At t=8 second, the acceleration of the lift is zero. Hence the weight of man=Mg

At t= 12seconds, the acceleratino of lift downwards=a_2=\dfrac{20-0}{14-10}m/s^2=5m/s^2
Hence weight of the man=M(g-a_2)

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