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Grade:7

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Shobhit Varshney IIT Roorkee
askIITians Faculty 33 Points
9 years ago
Hi,

Firstly, draw the v-t graph from this x-t graph.
v (= dx/dt) would be constant (20m/s) for first 2 seconds and then would be zero upto 6 seconds and then would be constant (-20m/s) upto 8 seconds.

Change in velocity = -20-(20) = -40 m/s
time duration = 8 seconds.

Average acceleration = -40/8 = -5m/s2

thanks

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