Particle moves up in air with initial velocity 100 m/s makes angle 60° with horizontal. The radius of curvature at t = 1 s is

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Vikas TU · Answer

At t=1 s, Vx = 100cos60 = 50 m/s and Vy = 100sin60 – g*1 = > 50root(3) – 10 = 75 m/s. Vnet = root(50^2 + 75^2) => 90.13 m/s. Radii of curvature would be = Perpendicular velocity to g/g => Vp/g Therefore, Vp = 90.13cos60 = > 45.06 approx. Hence, ROC = 45.06/10 = > 4.50 approx.

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Particle moves up in air with initial velocity 100 m/s makes angle 60° with horizontal. The radius of curvature at t = 1 s is

Particle moves up in air with initial velocity 100 m/s makes angle 60° with horizontal. The radius of curvature at t = 1 s is

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Particle moves up in air with initial velocity 100 m/s makes angle 60° with horizontal. The radius of curvature at t = 1 s is

Particle moves up in air with initial velocity 100 m/s makes angle 60° with horizontal. The radius of curvature at t = 1 s is

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