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Grade: 12th pass
`        Particle moves up in air with initial velocity 100 m/s makes angle 60° with horizontal. The radius of curvature at t = 1 s is`
3 years ago

## Answers : (1)

Vikas TU
10082 Points
```							At t=1 s,Vx = 100cos60 = 50 m/sandVy = 100sin60 – g*1 = > 50root(3) – 10 = 75 m/s.Vnet = root(50^2 + 75^2) => 90.13 m/s.Radii of curvature would be = Perpendicular velocity to g/g => Vp/gTherefore, Vp = 90.13cos60 = > 45.06 approx. Hence,ROC = 45.06/10 = > 4.50 approx.
```
3 years ago
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