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p { margin-bottom: 0.25cm; line-height: 120%; }a:link { } The position of a particle moving along X-axis is given by x=At+4Bt 3 .What is its velocity at t=5s?
Position of vector=At+Bt^3Velocity is given by=dx/dtVelocity=d(At+Bt^3)/dt=A+12Bt^2So velocity at 5s= A+12*(5)^2B=A+300B
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