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# p { margin-bottom: 0.25cm; line-height: 120%; }a:link { }The position of a particle moving along X-axis is given by x=At+4Bt3.What is its velocity at t=5s?

3 years ago

Onkar Joshi
24 Points
Position of vector=At+Bt^3Velocity is given by=dx/dtVelocity=d(At+Bt^3)/dt=A+12Bt^2So velocity at 5s= A+12*(5)^2B=A+300B

3 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions