0

Guest

Courses New

In factor it is desired to lift 2000 kg of metal through a distance of 12 m in 1m .find the minimum horsepower of the engine to be used.

In factor it is desired to lift 2000 kg of metal through a distance of 12 m in 1m .find the minimum horsepower of the engine to be used.

Grade:12th pass

1 Answers

Vikas TU
14149 Points
7 years ago
velocity with which it would lift => 0.5 * 2000 * v^2
and v = 0 + 10*1 = 10 m/s.
Therfore net work done would be = >  0.5 * 2000 * 10^2 + 2000* 10 * 12
                                                    => 340,000 Joule
Horse Power = > 340,000/746 = > 455.764 HP.

Think You Can Provide A Better Answer ?

Other Related Questions on Mechanics

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More