Hey there! We receieved your request
Stay Tuned as we are going to contact you within 1 Hour
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-5470-145
+91 7353221155
Use Coupon: CART20 and get 20% off on all online Study Material
Complete Your Registration (Step 2 of 2 )
Sit and relax as our customer representative will contact you within 1 business day
OTP to be sent to Change
Look at the figures is attachments. Here FF is the force applied and ff is force due to friction
F(cos α)=f cos β F (cos α)= f coβ (1)Also,f = μ N f = μ N (2)where, μμ is the coefficient of friction and NN is the normal reaction by the floor on the block.By force balance on the block along the vertical direction we getN= F sin α + f sin β + mg N=F sin α +f sin β + mg (3)subtracting 2 and 3 we getN = F sin α + mg ( 1 − μ sin β ) N = F sin α + mg ( 1 − μ sin β) (4)Now subtracting 2 and 4 we getF cos α = μ F sin α + mg ( 1 − μ sin β ) cos β F cos α = μ F sin α + mg ( 1 − μ sin β ) cos βF cos α ( 1− μ sin β ) =μ cos β ( F sin α + mg ) F cos α ( 1 – μ sin β ) = μ cos β ( F sin α + mg )F cos α ( 1 − μ sin β ) = F μ cos β sin α + μ mg cos β F cos α ( 1−μ sin β) =F μ cos β sin α+ μ mg cos βF [cos α− μ cos α sin β− μ cos β sin α ]= μ mg cos β F [ cos α –μ cos α sin β− μ cos β sin α ] = μ mg cos βF = μ mg cos β cos α – μ ( cos α sin β + cos β sin α ) F = μ mg cos β cos α – μ ( cos α sin β + cos β sin α )F = μ mg cos β cos α – μ sin ( α + β ) F = μ mg cos β cos α – μ sin ( α + β )since sin ( α + β ) = cos α sin β + cos β sin α sin ( α + β ) = cos α sin β + cos β sin α.F = F min = μ mg cos β cos α – μ sin ( α + β )
F = F min = μ mg cos β cos α – μ sin ( α + β ).
Get your questions answered by the expert for free
You will get reply from our expert in sometime.
We will notify you when Our expert answers your question. To View your Question
Win Gift vouchers upto Rs 500/-
Register Yourself for a FREE Demo Class by Top IITians & Medical Experts Today !