As we know that,
S = ut+½at²
u = 0 ( freefall )
Let total time be ‘t’
Total distance be ‘S’
So,
S/2 = ½(9.8)(T-1)² -[1]
S = ½(9.8)(T)² -[2]
From [1] & [2]
2{½(9.8)(T-1)²} = ½(9.8)(T)²
2(T-1)² = (T)²
√2(T-1) = T
T= √2/(√2–1)
T = 3.4142 second.
Three identical balls are placed on a frictionless
horizontal surface touching each other. They stick to
each other because of adhesive. Another ball of same
radius and mass m is placed over the void created by
the three balls. Find the forces applied by the balls
kept on the floor to each other if the system remains
in equilibrium.
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A car loaded with water having total mass 1000 kg moves on a straight horizontal Road starting from rest under the action of a force of 100 Newton. The water spills throw a small hole in the bottom at a rate of 0.1 KG per second the velocity of cart after 300 seconds is nearly.
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31
41
Last Activity: 9 Months ago
Last Activity: 3 Years ago
Last Activity: 3 Years ago
