×

#### Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
```
Four particles of mass M are placed at the vertices of a square with side L. What is the gravitational potential due to this at the center of the square.

```
3 years ago

toshita barua
11 Points
```							the length of each diagonal of the square is √2l. so here we get 4 particles with distances between any pair being l and 2 diagonal pairs for which the corresponding distance is √2l.      Now, the  P.E. of the system is    U =[(-4Gm^2)/l-(2Gm^2)÷√2l]       =(-5.41Gm^2)/lThe gravitational potential at the centre of the square is=4×[(-Gm)÷(√2l/2)=(-4√2Gm)÷l=(-5.64Gm)÷l (ans)
```
3 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Mechanics

View all Questions »

### Course Features

• 101 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution

### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions