Four particles of mass M are placed at the vertices of a square with side L. What is the gravitational potential due to this at the center of the square.

Question

toshita barua · Answer

the length of each diagonal of the square is √2l. so here we get 4 particles with distances between any pair being l and 2 diagonal pairs for which the corresponding distance is √2l. Now, the P.E. of the system is U =[(-4Gm^2)/l-(2Gm^2)÷√2l] =(-5.41Gm^2)/lThe gravitational potential at the centre of the square is=4×[(-Gm)÷(√2l/2)=(-4√2Gm)÷l=(-5.64Gm)÷l (ans)

Thank you for registering.

Register Now and Win Upto 25% Scholorship for a Full Academic Year !

Enter Your Details

Registration done!

Four particles of mass M are placed at the vertices of a square with side L. What is the gravitational potential due to this at the center of the square.

Four particles of mass M are placed at the vertices of a square with side L. What is the gravitational potential due to this at the center of the square.

1 Answers

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

Other Related Questions on Mechanics

ASK QUESTION

Answer and earn gift vouchers

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Complete Self Study Package designed by Industry Leading Experts

Live 1-1 coding classes to unleash the Creator in your Child

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Register Now & Win Upto 25% Scholorship