Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

Consider an ice cube of edge 1.0 cm kept in a gravity free hall. Find the surface area of the water when the ice melts. Neglect the difference in densities of ice and water.

Consider an ice cube of edge 1.0 cm kept in a gravity free hall. Find the surface area of the water when the ice melts. Neglect the difference in densities of ice and water.

Grade:10

4 Answers

Deepak Patra
askIITians Faculty 471 Points
7 years ago
Sol. Surface area = 4πr2
Koustav Saha
12 Points
6 years ago
Consider an ice cube of edge 1.0 cm kept in a gravity free hall.Find the surface area of water when the ice melts
 
Subodh Wasnik
41 Points
3 years ago
I am unable to solve it. I tried very but cannot get the steps for it. However i know the answer. Answer is (9π)^1/3
Subodh Wasnik
41 Points
3 years ago
Since ice is in gravity free space, thus after melting it forms a sphere. Area of ice cube= area of sphere1 cm3 =4/3πr^3=> r=(3/4π)^1/3Now, surfacr area is given byS.A.= 4πr^2 =4π(3/4π)^2/3 =(9π)^1/3

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free