#### Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Click to Chat

1800-5470-145

+91 7353221155

CART 0

• 0
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

# Consider an ice cube of edge 1.0 cm kept in a gravity free hall. Find the surface area of the water when the ice melts. Neglect the difference in densities of ice and water.

Deepak Patra
askIITians Faculty 471 Points
7 years ago
Sol. Surface area = 4πr2
Koustav Saha
12 Points
6 years ago
Consider an ice cube of edge 1.0 cm kept in a gravity free hall.Find the surface area of water when the ice melts

Subodh Wasnik
41 Points
3 years ago
I am unable to solve it. I tried very but cannot get the steps for it. However i know the answer. Answer is (9π)^1/3
Subodh Wasnik
41 Points
3 years ago
Since ice is in gravity free space, thus after melting it forms a sphere. Area of ice cube= area of sphere1 cm3 =4/3πr^3=> r=(3/4π)^1/3Now, surfacr area is given byS.A.= 4πr^2 =4π(3/4π)^2/3 =(9π)^1/3