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Consider a straight stick standing on end on (frictionless) ice. What would be the path of its center of mass if it falls?

Consider a straight stick standing on end on (frictionless) ice. What would be the path of its center of mass if it falls?

Grade:upto college level

3 Answers

erra akhil
208 Points
8 years ago
Straight line
Kevin Nash
askIITians Faculty 332 Points
8 years ago
The figure below shows the pencil falling on the frictionless surface and the path traced by its center of mass:
234-36_1.JPG
It can be seen from above that if enough samples of the falling pencil is taken, and the pencil is assumed to be symmetrical such that the center of mass lie at the center of the pencil, then the path traced by the center of mas of the pencil is a circle.
However, in reality there is friction and the shape is not symmetrical therefore the path traced by the center of mass of the pencil is a curved path.
Rutjay
15 Points
5 years ago
according to the qustion,
the path would be:
x^2 + y^2 = L^2/4
(the equation of a circle whose radii = L/2)...hope this helps
 

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