Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
`        Can somebody help me with this Q asap... Plz c attached image `
one year ago

Arun
22998 Points
```							Dear Adeel  Height of the fighter plane = 1.5 km = 1500 mSpeed of the fighter plane, v = 720 km/h = 200 m/sLet θ be the angle with the vertical so that the shell hits the plane.Muzzle velocity of the gun, u = 600 m/sTime taken by the shell to hit the plane = tHorizontal distance travelled by the shell = uxtDistance travelled by the plane = vtThe shell hits the plane. Hence, these two distances must be equal.uxt = vt usinΘ = vsinΘ = v/usinΘ = 200/600       = 1/3Θ = sin-1(0.33)Θ = 19.5 degrees RegardsArun (askIITians forum expert)
```
one year ago
Think You Can Provide A Better Answer ?

Other Related Questions on Mechanics

View all Questions »

Course Features

• 101 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution

Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions