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Can somebody help me with this Q asap... Plz c attached image
Dear Adeel Height of the fighter plane = 1.5 km = 1500 mSpeed of the fighter plane, v = 720 km/h = 200 m/sLet θ be the angle with the vertical so that the shell hits the plane.Muzzle velocity of the gun, u = 600 m/sTime taken by the shell to hit the plane = tHorizontal distance travelled by the shell = uxtDistance travelled by the plane = vtThe shell hits the plane. Hence, these two distances must be equal.uxt = vt usinΘ = vsinΘ = v/usinΘ = 200/600 = 1/3Θ = sin-1(0.33)Θ = 19.5 degrees RegardsArun (askIITians forum expert)
Height of the fighter plane = 1.5 km = 1500 m
Speed of the fighter plane, v = 720 km/h = 200 m/s
Let θ be the angle with the vertical so that the shell hits the plane.
Muzzle velocity of the gun, u = 600 m/s
Time taken by the shell to hit the plane = t
Horizontal distance travelled by the shell = uxt
Distance travelled by the plane = vt
The shell hits the plane. Hence, these two distances must be equal.
uxt = vt
usinΘ = v
sinΘ = v/u
sinΘ = 200/600
= 1/3
Θ = sin-1(0.33)
Θ = 19.5 degrees
Regards
Arun (askIITians forum expert)
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