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Grade: 12th pass
        
Can somebody help me with this Q asap... Plz c attached image
 
one month ago

Answers : (1)

Arun
16186 Points
							
Dear Adeel
 
 

Height of the fighter plane = 1.5 km = 1500 m

Speed of the fighter plane, = 720 km/h = 200 m/s

Let θ be the angle with the vertical so that the shell hits the plane.

Muzzle velocity of the gun, u = 600 m/s

Time taken by the shell to hit the plane = t

Horizontal distance travelled by the shell = uxt

Distance travelled by the plane = vt

The shell hits the plane. Hence, these two distances must be equal.

uxt = vt

 

usinΘ = v

sinΘ = v/u

sinΘ = 200/600

       = 1/3

Θ = sin-1(0.33)

Θ = 19.5 degrees

 

Regards

Arun (askIITians forum expert)

one month ago
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