Calculate the rotational inertia of a meter stick, with mass 0.56 kg, about an axis perpendicular to the stick and located at the 20-cm mark.

Question

Deepak Patra · Answer

Therefore, the rotational inertia of the meter stick about the axis perpendicular to its length and passing through center of mass is 0.047 kg·m 2 .

ankit singh · Answer

hence u just solve it easily thank u regards ankit singh keep it up just do smart works man thanku . . l l

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Calculate the rotational inertia of a meter stick, with mass 0.56 kg, about an axis perpendicular to the stick and located at the 20-cm mark.

Calculate the rotational inertia of a meter stick, with mass 0.56 kg, about an axis perpendicular to the stick and located at the 20-cm mark.

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Calculate the rotational inertia of a meter stick, with mass 0.56 kg, about an axis perpendicular to the stick and located at the 20-cm mark.

Calculate the rotational inertia of a meter stick, with mass 0.56 kg, about an axis perpendicular to the stick and located at the 20-cm mark.

2 Answers

Think You Can Provide A Better Answer ?

Other Related Questions on Mechanics

View courses by askIITians

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