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Grade 12th passMechanics

At time t(in seconds), a particle of mass 3kg has position vector r (meter) where r=3ti^-4costj^.The impulse of the force during the time interval 0-t-900 is
Ans-12j^ NS

Profile image of Kaushki
7 Years agoGrade 12th pass
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1 Answer

Profile image of nandhitha
6 Years ago
m=3kg
r=3ti^-4costj^
v=dr/dt=ti^=sintj^
a=dv/dt=costj^
since,f=ma
f=(3kg)(costj^)
inpulse=delta p=(F)(delta t)
                        = (f)(t final – t initial)
                        =(3)(costj^)(t final – t initial)
you can simplify the rest