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An object thrown vertically up from the ground passes the height 5m twice in an interval of 10 sec. What is its time of flight
An object thrown vertically up from the ground passes the height 5m twice in an interval of 10 sec. What is its time of flight

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5 years ago

Abhinav
387 Points
```							particle passes height 5mtwice in an interval of 10 sec .So it took 5 sec for reaching heighest point of flight.sovelocity at 5 m height is0= v- gt0=v-10*5v=50so speed at start =      502= u2- 2*10*5u= 51 m/stime taken to reach 5m =.1 secso total time of flight = 10.2
```
5 years ago
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• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions