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Grade: 12th pass
        
An elevator ascends from the ground with uniform speed. At time T1 a boy drops a marble through a hole in the floor. The marble hits the ground T2 seconds later. Find the height of the elevator at time T1.(T1=T2=4s)
5 months ago

Answers : (2)

downey zer
73 Points
							
Let the speed of the elevator be v
Then initially marble was also travelling at speed v.
when the marble fell from the hole the elevator was at height v*T1 as it was travelling at speed v for T1 time
now use 
h=ut+0.5at^2
where h = – v*T1
a= – g, u=v
t=T2
putting T1=T2=4
u will get v=10
so height =v*T1=40
5 months ago
downey zer
73 Points
							
please approve the answer if it helped
5 months ago
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