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`        An elevator ascends from the ground with uniform speed. At time T1 a boy drops a marble through a hole in the floor. The marble hits the ground T2 seconds later. Find the height of the elevator at time T1.(T1=T2=4s)`
8 months ago

downey zer
73 Points
```							Let the speed of the elevator be vThen initially marble was also travelling at speed v.when the marble fell from the hole the elevator was at height v*T1 as it was travelling at speed v for T1 timenow use h=ut+0.5at^2where h = – v*T1a= – g, u=vt=T2putting T1=T2=4u will get v=10so height =v*T1=40
```
8 months ago
downey zer
73 Points
```							please approve the answer if it helped
```
8 months ago
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## COUPON CODE: SELF10

### Course Features

• 101 Video Lectures
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• Mind Map
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions