Grade 10Mechanics

An elevator and its load have a combined mass of 1600 kg. Find the tension in the supporting cable when the elevator, originally moving downward at 12.0 m/s, is brought to rest with constant acceleration in a distance of 42.0 m.

Hrishant Goswami

11 Years agoGrade 10

2 Answers

Jitender Pal

11 Years ago

The negative sign in the acceleration indicates that the elevator is decelerating.

Therefore the tension in the supporting cable is 18,438.4 N .

Kushagra Madhukar

5 Years ago

Dear student,

Please find the solution to the problem.

Sign convention → Let the downward acceleration and velocity to be positive and the upward to be negative

We have, v² – u² = 2as

Hence, a = (0² – 12²)/2 x 42 = – 1.714 m/s²

Now, mg – T = ma

Hence, T = m(g – a)

= 1600(9.81 – ( – 1.714))

= 1600 x 11.524

= 18438.86 N = 18.44 kN

Thanks and regards,

Kushagra

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An elevator and its load have a combined mass of 1600 kg. Find the tension in the supporting cable when the elevator, originally moving downward at 12.0 m/s, is brought to rest with constant acceleration in a distance of 42.0 m.

Hrishant Goswami

2 Answers

Jitender Pal

Kushagra Madhukar

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