0

Guest

Courses New

An elevator and its load have a combined mass of 1600 kg. Find the tension in the supporting cable when the elevator, originally moving downward at 12.0 m/s, is brought to rest with constant acceleration in a distance of 42.0 m.

An elevator and its load have a combined mass of 1600 kg. Find the tension in the supporting cable when the elevator, originally moving downward at 12.0 m/s, is brought to rest with constant acceleration in a distance of 42.0 m.

Grade:10

2 Answers

Jitender Pal
askIITians Faculty 365 Points
9 years ago
235-1962_1.PNG
The negative sign in the acceleration indicates that the elevator is decelerating.
235-1870_1.PNG
Therefore the tension in the supporting cable is 18,438.4 N .
Kushagra Madhukar
askIITians Faculty 628 Points
3 years ago
Dear student,
Please find the solution to the problem.
 
Sign convention → Let the downward acceleration and velocity to be positive and the upward to be negative
We have, v2 – u2 = 2as
Hence, a = (02 – 122)/2 x 42 = – 1.714 m/s2
Now, mg – T = ma
Hence, T = m(g – a)
              = 1600(9.81 – ( – 1.714))
              = 1600 x 11.524
              = 18438.86 N = 18.44 kN
 
Thanks and regards,
Kushagra

Think You Can Provide A Better Answer ?

Other Related Questions on Mechanics

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More