0

Guest

Courses New

An astronaut has reached the surface of a distant planet. He drops a stone from the top of a cliff on the planet and observes that it takes t 1 = √2 sec to reach the bottom. He now throws another stone vertically upwards so that it reaches a height h = 1 m above the cliff before dropping down the cliff. The second stone takes a total time t 2 = 2 sec to reach the bottom of the cliff, starting from the time it leaves the astronaut's hand. The planet has a very thin atmosphere which affers negligible air resistance. What is the value of acceleration (in m/s) due to gravity on this planet?

An astronaut has reached the surface of a distant planet. He drops a stone from the top of a cliff on the planet and observes that it takes t 1 = √2 sec to reach the bottom. He now throws another stone vertically upwards so that  it reaches a height  h = 1 m above the cliff before dropping down the cliff. The second stone takes a total time t2 = 2 sec to reach the bottom of the cliff, starting from the time it leaves the astronaut's hand. The planet has a very thin atmosphere which affers negligible air resistance. What is the value of acceleration (in m/s) due to gravity on this planet?  

Grade:12

1 Answers

Eshan
askIITians Faculty 2095 Points
5 years ago
568-1119_123.png

Think You Can Provide A Better Answer ?

Other Related Questions on Mechanics

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More