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A weight suspended from free end of a vertically hanging spring produces an extension of 3 cm . The spring is cut into two parts so that the lenght of the longer part is 2/3 of the original lenght . If the same weight is now suspended from longer part of the spring the extension produced is
Weight is same hence, For same mass mg force,k1x1 = k2x2k*l = k’*(2l/3)we get,k’ = 3k/2 FOR natural length l spring,0.5k3^2 = mg*33k/2 = mg................(1) For 2l/3 length,0.5k’x^2 = mgxwe get,x = 2mg/(3k/2) from eq. (1)we get,x = 2 cm.
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