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`        A very large number of particles of same mass m kept at horizontal distance of 1m, 2m, 4m and 8m and so on from (0,0) point the total gravitational potential at point (0,0) is`
2 years ago

Arun
23755 Points
```							Dear Aditya Gravitational potential at point r is given by,V = - G*m/r According to the problem the gravitational potential by infinite masses at the origin is, V = -G*m (1 + 1/2 + 1/4 + 1/8+...) This is a geometric series with ratio 1/2So, V = -G*m*2.         As(sum of infinite terms of G.P. = 1/(1-1/2 ) = 2= - 2*G*m RegardsArun(askIITians forum expert)
```
2 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions