Grade upto college level Mechanics
A vectors ![src=data:image/png;base64,iVBORw0KGgoAAAANSUhEUgAAABIAAAAYCAIAAAB4NzpmAAAAhUlEQVQ4jeWR0RGAMAhDmSsDMU+mYRmG0Y96VgutvZ4/nvnj4yUBZFuS/BkzFbWVNCcCmWKmEnQH30xrktd2y9TB6nagEaA/Yk7UExQ+1AyYEyLV3YmECpjp3dwJCRUD1pp3wlrM9NqwSw2xcpuk4qikKcjDxdsfhEuedivOr08zfZvQJbAeAR4pAjtIdTQAAAABJRU5ErkJggg==]()
of magnitude 12 units and another vector ![src=data:image/png;base64,iVBORw0KGgoAAAANSUhEUgAAABMAAAAYCAIAAACX9VFYAAAAkUlEQVQ4jbWUyw3AIAxDM5cHyjyeJstkmPZEodRQhNrcEHmyHT527Jb9TYabx6ZmEndYkuE2qIb9WFO62M75KE2WoL3Okmb4HBySSRiYG2T4C3iY3i5eJ4E1mYQ5ywmGK3Yy28ttEvb0Prx9Tec62c912W0St0YNKrLz2i0nZBJVQ0fUZBJg1hc6vIG//0OfkifDGcAJC0nypQAAAABJRU5ErkJggg==]()
of magnitude 5.8 units point in directions differing by 55°. Find the scalar product of the two vectors.
1 Answer
Navjyot Kalra
Substituting 12 units is the magnitude of a and 5.8 units is the magnitude of b and 55̊ for the direction ϕ in the equation a . b = ab cosϕ,
a . b = ab cosϕ
= (12) (5.8) cos 55̊)
= 39.93 …… (2)
Rounding off to one significant figure, scalar product of two vectors will be 40.
a . b = ab cosϕ
= (12) (5.8) cos 55̊)
= 39.93 …… (2)
Rounding off to one significant figure, scalar product of two vectors will be 40.
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