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A vectors of magnitude 12 units and another vector of magnitude 5.8 units point in directions differing by 55°. Find the scalar product of the two vectors. A vectors of magnitude 12 units and another vector of magnitude 5.8 units point in directions differing by 55°. Find the scalar product of the two vectors.
Substituting 12 units is the magnitude of a and 5.8 units is the magnitude of b and 55̊ for the direction ϕ in the equation a . b = ab cosϕ,a . b = ab cosϕ = (12) (5.8) cos 55̊) = 39.93 …… (2)Rounding off to one significant figure, scalar product of two vectors will be 40.
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