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A tube has two area of cross- sections as shown in figure. The diameters of the tube are 8 mm and 2 mm. Find range of water falling on horizontal surface, if piston is moving with a constant velocity of 0.25 m/s, h = 1.25 m (g = 10 m/s 2 )

A tube has two area of cross- sections as shown in figure. The diameters of the tube are 8 mm and 2 mm. Find range of water falling on horizontal surface, if piston is moving with a constant velocity of 0.25 m/s, h = 1.25 m (g = 10 m/s2)

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Grade:11

1 Answers

Kevin Nash
askIITians Faculty 332 Points
6 years ago
Hello Student,
Please find the answer to your question
From law of continuity
A1 v1 = A2 v2
Given A1 = π x (4 x 10-3 m)2 , A2 = π x (1 x 10-3 m)2
v1 = 0.25 m/s
∴ v2 = π x (4 x 10-3)2 x 0.25 / π x (1 x 10-3)2
Also, h = 1 /2 gt2 ⇒ t = √2h / g
Horizontal range x = v2 √2h / g = 4 x √ 2 x 1.25 / 10 = 2 m
Thanks
Kevin Nash
askIITians Faculty

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