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a train travelling at 20km/hr is approaching a platform a bird is siiting on a pole on the platform when the train is at a distance of 2 km from the pole brakes are applied which produce a uniform deceleration in it at that instant the bird flies towards the train at 60km/hr and after touching the nearest point on the train flies back to the pole and then flies towards the train and continues repeating itself calculate how much distance will the bird have flown before the train stopps

palak singhal , 10 Years ago
Grade 11
anser 4 Answers
Arun Kumar

Last Activity: 10 Years ago

Hi

Since the train has to stop at the station
So



Thanks & Regards, Arun Kumar, Btech,IIT Delhi, Askiitians Faculty

palak singhal

Last Activity: 10 Years ago

Alok mishra

Last Activity: 6 Years ago

The above answer is 100%wrong the correct answer is :
V2=u2+2as
0=400+2×a×2
Hence a=-100km/hr2
Now,v=u+at
T=1/5sec
Now the time bird would fly is equal to time travel by train so v×t=distance covered by bird
So, 1/5×60=distance traveled by bird
=12km

Mana Ranjan Mishra

Last Activity: 5 Years ago

The above mentioned answer is right but the time calulacalc above is written as 1/5sec. That should be written as 1/5 hr.

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