Falling Behind in Studies? Join Our Performance Improvement Batch. Enroll For Free
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
A thin uniform rod oflength "L" is bentits mid point as shown in the figure.distance of the centre of mass from the p"O" is
Length of rod =LNow as it bends from its mid point ,Length of each segment is =L/2As it is a uniform rod ,Therefore considering 1st n 2nd segment of rod separately COM of each segment =L/4Now since 1st segment is along d X axis & 2nd makes an angle `@` with -ve X axis ..... Or `180-@` with +ve X axis By applying Xcm={ (m/2)×(-l/4) + (l/4cos(180-@))}÷(m/2+m/2)=. -l(1+cos)/8Similarly for Ycm ={ (m/2)×l/4sin(180-@)}÷{m/2+m/2}=Lsin@/8Now to calculate final answer .....√Xcm sq + Ycm sq = on simplifying...I.e taking LCM..=L√ 2(1+cos@)/8= L/8×cos (@/2). {1+cos @=2cos sq @/2}
Post Question
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -