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`        a stone is thrown vertically upward from the top of a tower 70m high with a velocity of 19.2m/s.determine the position and velocity when t=6s.`
2 years ago

Mohit Dhaka
46 Points
```							Taking g=9.6 Here th ball will come back to its original position ang velocity opposite to it in 4 sec soafter the using kinematicsu=19.2 t=2 a=9.6  we find s=48m and v=38.4 so ball is 48 m down the initial position and velocity of 38.4 downwards there might be some calculation mistakes so plese dont mind them only think of the concept
```
2 years ago
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### Course Features

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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions