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`        A stone is dropped from the top of a tower 100m high. Another stone is projected upwards at the same time from the foot of the tower , and meets the first stone at a height of 30m . Find the velocity with which the second stone is projected upwards . Take g=9.81ms-2`
one year ago

Saurabh Koranglekar
3163 Points
```							Dear studentTime taken by stone1 to cover 70m fall = time take by stone 2 to cover 30 m upwards(2*70/9.81)^0.5 = t..................i30 = ut – (9.81/2)*t^2........................iiuse i to find time tplug in t in eq ii
```
one year ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions