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`        A spring fixed at the bottom end of an incline of inclination 37º. A small block of mass 2 kg starts slipping down the incline from a point 4.8 m away from the spring. the block compresses the spring by 20 cm, stops momemtarily and then rebounds through a distance of 1 m up the incline. find the spring constant of the spring.`
3 years ago

Vikas TU
10490 Points
```							From the WET we get,mg(4.8sin37) = 0.5*k*(0.2)^2 + 0.5mv^257.6  = 0.02k + v^2.............(1)From bottom to top, applying WET we get,0.5*2*v^2 = mg(1*sin37)orv^2 = 12.....(2)put (2) in eqn. (1)we get,0.02k = 57.6 – 12 => 45.6k = 45.6/0.02 => 4560/2 => 2780
```
3 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions