A spring balance is attached to the ceiling of a lift. A man hangs his bag on the spring and the spring reads 49 N, when the lift is stationary. If the lift moves downward with an acceleration of 5 m/square second, the reading of the spring balance will be:

Question

Niraj Bishnoi · Answer

R=mg=49N I.e mass = 49/9.8 = 5kgWhen moving down,Ma =Mg-Ror R=Mg-Ma= 49 - 5x5= 49-25=24Direction convention- upward -ve downward +ve

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A spring balance is attached to the ceiling of a lift. A man hangs his bag on the spring and the spring reads 49 N, when the lift is stationary. If the lift moves downward with an acceleration of 5 m/square second, the reading of the spring balance will be:

A spring balance is attached to the ceiling of a lift. A man hangs his bag on the spring and the spring reads 49 N, when the lift is stationary. If the lift moves downward with an acceleration of 5 m/square second, the reading of the spring balance will be:

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A spring balance is attached to the ceiling of a lift. A man hangs his bag on the spring and the spring reads 49 N, when the lift is stationary. If the lift moves downward with an acceleration of 5 m/square second, the reading of the spring balance will be:

A spring balance is attached to the ceiling of a lift. A man hangs his bag on the spring and the spring reads 49 N, when the lift is stationary. If the lift moves downward with an acceleration of 5 m/square second, the reading of the spring balance will be:

1 Answers

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