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A small block of mass m is kept on a rough inclined surface of inclination θ fixed in an elevator. The elevator goes up with a uniform velocity v and the block does not slide on the wedge. The work done by the force of friction on the block in time t will be Options: Zero mgvt cos2θ mgvt sin2θ mgvt sin2θ

A small block of mass m is kept on a rough inclined surface of inclination θ fixed in an elevator. The elevator goes up with a uniform velocity v and the block does not slide on the wedge. The work done by the force of friction on the block in time t will be

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Grade:12th pass

1 Answers

Arun
25750 Points
6 years ago
Dear Dipak
Draw the FBD . u will get f =mg sinθ now break f into perpendicular components.

here fsinθ will act in downward drtn. and f cosθ in a direction perpendicular to motion.

so the work will be done by f sinθ.

work done=mgsin2θ * h   

h = height travelled in time t

h = v t

Hence

Work done = mg vt sin²θ 

Regards

Arun (askIITians forum expert)

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