A small block of mass m is kept on a rough inclined surface of inclination θ fixed in an elevator. The elevator goes up with a uniform velocity v and the block does not slide on the wedge. The work done by the force of friction on the block in time t will beOptions:Zeromgvt cos2θmgvt sin2θmgvt sin2θ
Dipak Bhowmik , 6 Years ago
Grade 12th pass
1 Answers
Arun
Last Activity: 6 Years ago
Dear Dipak
Draw the FBD . u will get f =mg sinθ now break f into perpendicular components.
here fsinθ will act in downward drtn. and f cosθ in a direction perpendicular to motion.
so the work will be done by f sinθ.
work done=mgsin2θ * h
h = height travelled in time t
h = v t
Hence
Work done = mg vt sin²θ
Regards
Arun (askIITians forum expert)
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