A small ball of mass m moving with velocity v strikes a rough surface u(frictional coefficient) at an angle A with the vertical if the vertical component of velocity of the ball just after impact is found to be v÷2 in upward direction then the horizontal velocity of ball after impact in horizontal direction?

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Arun · Answer

Dear Utkarsh Hence V sin theta = V/2 Sin theta = &frac12; Hence Theta = 30&deg; Now horizontal component = V cos theta = V cos 30 = (V /2) * sqrt(3) Regards Arun (askIITians forum expert)

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