Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
`        A small ball of mass m moving with velocity v strikes a rough surface u(frictional coefficient) at an angle A with the vertical  if the vertical component of velocity of the ball just after impact is found to be v÷2 in upward direction then the horizontal velocity of ball after impact in horizontal direction?`
2 years ago

Arun
23357 Points
```							Dear Utkarsh

Hence
V sin theta = V/2
Sin theta = ½
Hence
Theta = 30°
Now horizontal component = V cos theta
= V cos 30 = (V /2) * sqrt(3)

Regards
```
2 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Mechanics

View all Questions »

### Course Features

• 101 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution

### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions