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Grade: 12th pass
        A small ball of mass m moving with velocity v strikes a rough surface u(frictional coefficient) at an angle A with the vertical  if the vertical component of velocity of the ball just after impact is found to be v÷2 in upward direction then the horizontal velocity of ball after impact in horizontal direction?
10 months ago

Answers : (1)

Arun
14933 Points
							
Dear Utkarsh
 
Hence
V sin theta = V/2
Sin theta = ½
Hence
Theta = 30°
Now horizontal component = V cos theta
 = V cos 30 = (V /2) * sqrt(3)
 
Regards
Arun (askIITians forum expert)
10 months ago
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