Grade 11Mechanics

A SATELLITE ORBITS THE EARTH AT A HEIGHT EQUAL TO THE RADIUS OF THE EARTH FIND ITS 1)ORBITAL SPEED AND2)PERIOD OF REVOLUTION

Kevin Suchetan

8 Years agoGrade 11

1 Answer

sam

8 Years ago

Let V be the orbital speed of the satellite.

Then,

The centripetal acceleration required by it to move in an orbit of radius 2R( measured from the centre of the Earth) would be provided by the gravitaional force of atraction between Earth and the satellite.

Hence,

mV²/2R = GMm/4R²

V² = GM/2R

Hence

V= (GM/2R)^1/2 ...(i)

Now for period of revolution,

We know

Time = Distance/ Speed

Therefore,

T = (2*Pi*2R) / V ...(ii)

Substitute the value of V in (ii) to get the time period

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A SATELLITE ORBITS THE EARTH AT A HEIGHT EQUAL TO THE RADIUS OF THE EARTH FIND ITS 1)ORBITAL SPEED AND2)PERIOD OF REVOLUTION

Kevin Suchetan

1 Answer

sam

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