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A SATELLITE ORBITS THE EARTH AT A HEIGHT EQUAL TO THE RADIUS OF THE EARTH FIND ITS 1)ORBITAL SPEED AND2)PERIOD OF REVOLUTION
A SATELLITE ORBITS THE EARTH AT A HEIGHT EQUAL TO THE RADIUS OF THE EARTH FIND ITS 1)ORBITAL SPEED AND2)PERIOD OF REVOLUTION

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3 years ago

sam
22 Points
```							Let V be the orbital speed of the satellite.Then,The centripetal acceleration required by it to move in an orbit of radius 2R( measured from the centre of the Earth) would be provided by the gravitaional force of atraction between Earth and the satellite.Hence, mV2/2R = GMm/4R2V2 = GM/2RHence V= (GM/2R)^1/2       ...(i)Now for period of revolution,We know Time = Distance/ SpeedTherefore,T = (2*Pi*2R) / V     ...(ii)Substitute the value of V in (ii) to get the time period
```
3 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions