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A roller of mass 300 kg and of radius 50cm is lying on horizontal floor is resting against a step of height 20cm. The minimum horizontal force to be applied on the roller passing through its centre to turn the roller on the step.

A roller of mass 300 kg and of radius 50cm is lying on horizontal floor is resting against a step of height 20cm. The minimum horizontal force to be applied on the roller passing through its centre to turn the roller on the step.

Grade:10

1 Answers

Vikas TU
14149 Points
7 years ago
Net torque about the line joining the step size and cyclinder = 0 Hence,
F x (50 – 20) = Mg x R
We get,
F = 5Mg/3 => 5000N
would be the toppling horizontal force required to turn the roller onto the step.

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