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A REAR SIDE OF A TRUCK IS OPEN AND A BOX OF 40KG MASS IS PLACED 5M AWAY FROM THE OPEN END .THE COFFICIENT OF FRICTION BETWEEN THE BOX AND THE SURFACE BELOW IT IS 0.15.ON A STRAIGHT ROAD , A TRUCK STARTS FROM REST AND ACCELRATES WITH 2M/S 2 . AT WHAT DISTANCE FROM THE STARTING POINT DOES THE BOX FALL OF THE TRUCK ? AFTER IGNORING THE MASS OF THE BOX
A REAR SIDE OF A TRUCK IS OPEN AND A BOX OF 40KG MASS IS PLACED 5M AWAY FROM THE OPEN END .THE COFFICIENT OF FRICTION BETWEEN THE BOX AND THE SURFACE BELOW IT IS 0.15.ON A STRAIGHT ROAD , A TRUCK STARTS FROM REST AND ACCELRATES WITH 2M/S2 . AT WHAT DISTANCE FROM THE STARTING POINT DOES THE BOX FALL OF THE TRUCK ? AFTER IGNORING THE MASS OF THE BOX

```
3 years ago

Aman
22 Points
```							Take Right as + . Pseudo force on block=a trck×mas blck=80 normal on blck=wt=400 friction on blck =-60 net horizontal force =80-60=20 acceleration of block w r t trck=20/40=1/2 displacement of block w rt trck is 5 and initial velocity is 0.so time after blck fall= root 20 . S from start point=s of trck in time root20= 20
```
3 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions