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`        a PROJECTILE is thrown at an angle 30° with initial velocity 50 cm/s .when it is at the highest point it explodes and breaks into ratio 1:3 .the smaller part falls down vertically .find the distance where the heavier part lands.`
3 years ago

Vikas TU
10073 Points
```							From momentum conservation in x and y direcn. separetely we get,In x direcn.Mvcos30 = M/4*0 + (3M/4)v’v’ = 2*v*root(3)/3 m/sIn y direcn.Mvsin30 = + v0*3M/4v0 = 2v/3Resultant velocity of heavier mass =>=> root((2v/3)^2 + (2*v*root(3)/3)^2)=> root(4v^2/9 + 4v^2/3)=> root(16v^2/9)=> 4v/3 m/sDistance travelled,(4v/3)^2 = v^2 + 2gswe get,s = 7v^2/18g  = 7*0.25/180  = 9.72222 x 10^-3 meter.
```
3 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions