×

#### Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
```
A projectile is thrown at 60° with the horizontal. After 4s it is moving perpendicular to its initial direction of motion. If g = 10 m/s^2 , then initial speed of throw is
A projectile is thrown at 60° with the horizontal. After 4s it is moving perpendicular to its initial direction of motion. If g = 10 m/s^2 , then initial speed of throw is

```
3 years ago

## Answers : (1)

Prashant Kumar
21 Points
```							For this type of questions Simply use the formulaT=u/g*sinθSol. T=4θ= 60°Substitute the values4= u/10* sin60°Sin60°= √3/2=>U= 4*10*√3/2   = 20√3 m/sAns correct
```
3 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies

## Other Related Questions on Mechanics

View all Questions »

### Course Features

• 101 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution

### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions