Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
A projectile is projected on a smooth inclined plane in direction perpendicular to line of greatest slope with a velocity of 8m/s Find its speed after 1s
Instantaneous magnitude of velocity is speed thus for speed to be constant implement magnitude of instantaneous velocity remains constant so direction can change for velocity to be changing
Initial speed of the projectile (ball) u = 8 m/sLet the inclined plane make an angle α with the horizontal. The component of g along the plane is- g sin α and perpendicular to the plane is g cos α. Let the ball be projected in the direction perpendicular to the line of greatest slope (i.e. the slope of the inclined plane itself). So The angle of projection θ can be taken as 0. Now the equations for the horizontal and vertical components of the velocity after time t are given byvx = u cos θ - g sin α x tvy = u sin θ + g cos α x tVelocity after time t = (vx2 + vy2)½If the angle of inclination α is known we can find v.
Find solution of question on doubt solving app Instasolv
Post Question
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -