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Grade: 11
        
A particle of mass m tied with a string of length l is released from a horizontal position . Find the velocity at lowest position 
3 months ago

Answers : (2)

Arun
22993 Points
							
A particle of mass m attached to end of the string of length l is released from horizontal position. 
then, energy at horizontal position of particle = energy at lowest position of particle.
Let at lowest position speed of particle = v
now, mgl = 1/2 mv² 
v = √2gl 
now we should find speed of particle at highest position . Let v' be the speed of particle at highest position .
so, mg(2l) + 1/2mv'² = 1/2 mv² 
2mgl + 1/2mv² = 1/2mg(2gl) = mgl 
1/2mv² = -mgl 
v² = -2gl , here v is imaginary number .
means this situation is not possible . if we released particle from horizontal position , particle doesn't complete circle
 
3 months ago
Harsh
47 Points
							
As the particle is at horizontal position,let its height from the lowest position be h.
Applying conservation of energy on the system we get
Ke at horizontal position+pr wt horizontal position=
Ke at lower position+ pe at lower position.
Hence,
0+mgh=1/2mv²+0
mgh=1/2mv²
gh=1/2mv²
V=√2gh.
3 months ago
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