A particle of mass m is projected making an angle theta with the horizontal. Find the power exerted by gravity at half of the max h max height

Question

Vikas TU · Answer

At half of the maximum height => h = u^2/g u = root(gh) m/s. Now, Power = F x velocity => mg x root(gh) Watt.

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A particle of mass m is projected making an angle theta with the horizontal. Find the power exerted by gravity at half of the max h max height

A particle of mass m is projected making an angle theta with the horizontal. Find the power exerted by gravity at half of the max h max height

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A particle of mass m is projected making an angle theta with the horizontal. Find the power exerted by gravity at half of the max h max height

A particle of mass m is projected making an angle theta with the horizontal. Find the power exerted by gravity at half of the max h max height

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