consider a hexagon placed in X-Y plane whose bottom side is on x axis...
first u draw this figure ...
let its two vertex which are on x axis are A,B & particle is moving from A to B along +ve x axis...
initial velocity of particle is U =vi
at point B its velocity changes in direction...its velocity makes an angel of 60 degree with x axis ..
final velocity is Vf= vcos60i + vsin60j=(i + sqrt3.j)v/2
change in velocity is = final velocity - initial velocity
=(v/2-v)i + sqrt3.vj/2
=-vi/2 + sqrt3.vj/2
impulse = mdv=mv/2 (-i + sqrt3j)
I= mv in magnitude
Regards
Arun
Three identical balls are placed on a frictionless
horizontal surface touching each other. They stick to
each other because of adhesive. Another ball of same
radius and mass m is placed over the void created by
the three balls. Find the forces applied by the balls
kept on the floor to each other if the system remains
in equilibrium.
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A car loaded with water having total mass 1000 kg moves on a straight horizontal Road starting from rest under the action of a force of 100 Newton. The water spills throw a small hole in the bottom at a rate of 0.1 KG per second the velocity of cart after 300 seconds is nearly.
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