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        A particle moves in a straight line. its speed increases linearly with time. if the inital speed of the particle is V0 and it's speed at t=4s is 2V0 then 0 ∫ 4 v dt is equal to? (ans is 6V0).Pls explain the answer. thanks in advance
one year ago

Khimraj
3008 Points
							v = ct + dwhere c and d are constantat t = 0, v= vovo = dso v = ct + voat t=4, v = 2vo2vo = c*4 + voc = vo/4so v = vo(t/4 + 1)so $\int_{0}^{4}vdt$ = $(v_{o})\int_{0}^{4}(t/4 + 1)dt = 6v_{o}$Hope it clears....................................

one year ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions