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Grade: 12th pass
        
a particle is projected horizontally with speed u from point a which is 10m above the ground .if the particle hits the inclined plane perpendicularly at point B
3 years ago

Answers : (1)

Vikas TU
9510 Points
							
  1. Apply eqn. of motions.
x = 0 + 0.5gt^2 {let it covered x distance after hitting the incline.}
in horztl. 
10 – x = u*t..............(2)
{from geomtery}
Now we need one more eqn.
Displacement OB = root2*(10-x)
Now,
Final velocity,
vx = u in x direcn
and
vy = gt in y direcn.
v = root(u^2 + (gt)^2)
Now,
v.(OB) = 0 (Dot Product is zero).
3 years ago
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