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`        A particle is projected from the ground in a vertical direction at t=0. At t=0.8sec, it reaches h=14m. It will again come to the same height at t=? [g=10m/s2`
2 years ago

Arun
23739 Points
```							Dear Ayush h= v₀•t-g•t²/2 , v₀=h/t +gt/2 = 14/0.8 +9.8•0.8/2 = 21.42 m/s. Time of the motion to the highest point t₀=v₀/g =21.42/9.8=2.19 s. t1=2•2.19 – 0.8=3.58 s.
```
2 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions