Falling Behind in Studies? Join Our Performance Improvement Batch. Enroll For Free
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
A particle is moving along a straight line such that its acceleration can be given as a=3-4t, where t is in second. At t=0, its velocity is v=2m/s. Distance travelled by particle in 3 s is
Now a=3-4t i.e dv/dt =3-4t => v= 3t-2t2 +C ; where C is a constant. given at t=0 v=2m/s so C=2. Now v = 3t-2t2 + 2 i.e. ds/sdt =3t-2t2 +2 => s =3t2/2-2t3/3+2t + K now distance travelled in 3 sec will be given by s(3)-s(0)Here s(3)-s(0)= 3*9/2-2*27/3+6+K -(0+0+0+K) =27/2-18+6 =1.5m
Post Question
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -