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A particle is moving along a circle such that it completes one revolution in 40 seconds. In 2 minutes 20 seconds, the ratio of | displacement| : distance is: 0 1/7 2/7 1/11

A particle is moving along a circle such that it completes one revolution in 40 seconds. In 2 minutes 20 seconds, the ratio of | displacement| : distance is:
  1. 0
  2. 1/7
  3. 2/7
  4. 1/11

Grade:12th pass

2 Answers

Saurabh Koranglekar
askIITians Faculty 10335 Points
4 years ago
576-1976_IMG_20200403_072921.jpg
Vikas TU
14149 Points
4 years ago
1 rev=40sec
1/40rev=1 sec
In 2 min 20sec
We know 1 min =60sec
So2 min =120 sec
120+20=140 sec
1/40×140rev=140 sec= 7/2 rev or 3.5 rev
i.e. it completes 3 full rev. And half rev.
We know that circumference for 1 full circle = 2pie r
And for half= 2 pie r/2= pie r
I.e. 3.5rev= 3×2pie r + pie r= 7 pie r
7 pie r = distance
For displacement we know it completes 3.5 rev which is curcular owiously so when it completes 3 rev. It starts from a point and only where full circular rev. End i.e. from which point it starts there only it ends i.e displacement =0 for 3 rev. But half i.e. 0.5 rev. Is still left or half rev. Distance = pie r but displacement is not pie r uts 2r
so,here the total displacement= 2r
And we r asked about ratio= displacement/ distance which is= 2r/ 7 pie r
We all know pie=22/7
Ratio= 2r×7/ 7×22×r= 1/11
 
 

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