Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
A particle is moving along a circle such that it completes one revolution in 40 seconds. In 2 minutes 20 seconds, the ratio of | displacement| : distance is: 0 1/7 2/7 1/11
1 rev=40sec1/40rev=1 secIn 2 min 20secWe know 1 min =60secSo2 min =120 sec120+20=140 sec1/40×140rev=140 sec= 7/2 rev or 3.5 revi.e. it completes 3 full rev. And half rev.We know that circumference for 1 full circle = 2pie rAnd for half= 2 pie r/2= pie rI.e. 3.5rev= 3×2pie r + pie r= 7 pie r7 pie r = distanceFor displacement we know it completes 3.5 rev which is curcular owiously so when it completes 3 rev. It starts from a point and only where full circular rev. End i.e. from which point it starts there only it ends i.e displacement =0 for 3 rev. But half i.e. 0.5 rev. Is still left or half rev. Distance = pie r but displacement is not pie r uts 2rso,here the total displacement= 2rAnd we r asked about ratio= displacement/ distance which is= 2r/ 7 pie rWe all know pie=22/7Ratio= 2r×7/ 7×22×r= 1/11
Post Question
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -