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A particle is moving along a circle such that it completes one revolution in 40 seconds. In 2 minutes 20 seconds, the ratio of | displacement| : distance is: 0 1/7 2/7 1/11
A particle is moving along a circle such that it completes one revolution in 40 seconds. In 2 minutes 20 seconds, the ratio of | displacement| : distance is:	0	1/7	2/7	1/11

```
9 months ago

Saurabh Koranglekar
10341 Points
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```
9 months ago
Vikas TU
14149 Points
```							1 rev=40sec1/40rev=1 secIn 2 min 20secWe know 1 min =60secSo2 min =120 sec120+20=140 sec1/40×140rev=140 sec= 7/2 rev or 3.5 revi.e. it completes 3 full rev. And half rev.We know that circumference for 1 full circle = 2pie rAnd for half= 2 pie r/2= pie rI.e. 3.5rev= 3×2pie r + pie r= 7 pie r7 pie r = distanceFor displacement we know it completes 3.5 rev which is curcular owiously so when it completes 3 rev. It starts from a point and only where full circular rev. End i.e. from which point it starts there only it ends i.e displacement =0 for 3 rev. But half i.e. 0.5 rev. Is still left or half rev. Distance = pie r but displacement is not pie r uts 2rso,here the total displacement= 2rAnd we r asked about ratio= displacement/ distance which is= 2r/ 7 pie rWe all know pie=22/7Ratio= 2r×7/ 7×22×r= 1/11
```
9 months ago
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• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions