0

Guest

Courses New

A particle is dropped from tower of 2080 m. At the same time second particle is thrown vertically in upward direction at 130 m/s. At what height they both will meet together. Please explain solution too.

A particle is dropped from tower of 2080 m.  At the same time second particle is thrown vertically in upward direction at 130 m/s. At what height they both will meet together. Please explain solution too.

Grade:12th pass

2 Answers

Apoorva Arora IIT Roorkee
askIITians Faculty 181 Points
9 years ago
The time taken for both will be equal since they are thrown at the same instant. Also, The distance travelled by one will be 2080 minus the distance travelled by the other particle.
So we write the two eq of motion as
1. s=0\times t+\frac{1}{2}\times 10\times t^{2}
2. 2080-s=130\times t-\frac{1}{2}\times 10\times t^{2}
adding 1 and 2
we get
2080=130t
hence t= 16 seconds
so height is 800 metres
Thanks and Regards
Apoorva Arora
IIT Roorkee
askIITians Faculty
Abhishek Shukla
18 Points
9 years ago
Thanks a lot sir!!! :) 

Think You Can Provide A Better Answer ?

Other Related Questions on Mechanics

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More