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`        A particle at rest is dropped under gravity from height h and it travels a distance 9h/25 in the last second find the height `
one year ago

Arun
23358 Points
```							Dear Prabhat As the particle is dropped then u = 0        As we all know that g = 9.8 m/s^2.Then from the third equation of motion=S = ut+1/2 gt^2S = ½ gt^2where t is the total time taken	Distance covered in (t-1) sec = h -9h/25 = 16h/25Solving (1.) and (2.)T = 5sSubstituting the value of t in eq. 1S = ½ *9.8 *25S = 122.5 m
```
one year ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions